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X^2-2X-25.6=0
a = 1; b = -2; c = -25.6;
Δ = b2-4ac
Δ = -22-4·1·(-25.6)
Δ = 106.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{106.4}}{2*1}=\frac{2-\sqrt{106.4}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{106.4}}{2*1}=\frac{2+\sqrt{106.4}}{2} $
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